Here we are talking about Ages" related the quantitative aptitude test. So many students are thinking its very tuff part in competitive exams. But once if we get the logics its very easy subject and also it helps improve the thinking capability our mind.

Now a days each and every competitive exams they asked Problems on ages. if you know the tricks and do the good practice you can get good knowledge on relations and even you will never miss atleast one answer on this topic. So that It can fetch you full marks. who are preparing for IBPS, SSC, SBI, RRB or any other exams should have easy hands on age topic for getting good score.

1. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

A.35

B.40

C.45

D.30

Answer : Option A

Explanation :

Let the present P and Q age is : 3x and 4x respectively.

whenever comes these type of questions like ten years "ago"(-) Page is 3x-10 and Q age is 4x-10.

Ten years ago, P was half of Q in age

=>(3x–10)=½(4x–10)

=>6x–20=4x–10

=>2x=10

=>x=5

Total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

2. Father is aged three times more than his son Ranjit. After 8 years, he would be two and a half times of Ranjit's age. After further 8 years, how many times would he be of Ranjit's age?

A.3 times

B.21/2times

C.23/4times

D.2 times

Answer: Option D

Explanation:

Let Ranjit's present age be x years.

if Ranjit's age = x then Father's age = 3x

But Here given statement 3 times more than his son. so 4x.

Then, father's present age =(x + 3x) years = 4x years.

(4x + 8)=5/2(x + 8)

8x + 16 = 5x + 40

3x = 24

x = 8.

after further 8 years,

Hence, required ratio

=>4x+8+8=x+8+8

=>(4x+16)/(x+16)

=>48/24=>2

3. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju

A. 15

B. 14

C. 8

D. 10

Answer: Option D

Explanation:

Let the present Raju age is x, After 15 years Raju age is x+15

If the present Raju age is x, 5 years back Raju age is x-5

Raju age after 15 years will be 5 times his age 5 years back

x+15 = 5(x-5)

=> 4x = 40 => x = 10

4. The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years

A. 7:9

B. 7:8

C. 3:8

D. 5:8

Answer: Option B

Explanation:

Let P age and Q age is 6x years and 7x years.

If Q is 4 years old than P

Then 7x - 6x = 4 <=> x = 4

after 4 years P and Q ages Ratio is

So required ratio will be (6x+4):(7x+4) => 28:32 => 7:8

5. At present the age of the father is five times that of the age of his son. Three years hence, the father’s age would be four times that of his son. Find the present ages of the father and the son.

A. 35

B. 45

C. 40

D. 55

Answer: Option B

Explanation:

Let the present age of son = x years.

Then, the present age of father = 5x years.

3 years hence.i.e after three years (x + 3) = 5x + 3

The father’s age would be four times that of his son

4(x + 3) = 5x + 3

or, 4x + 12 = 5x + 3

x = 9 years.

Therefore, son’s age = 9 years

and father’s age = 5x=5x9=45 years.

Now a days each and every competitive exams they asked Problems on ages. if you know the tricks and do the good practice you can get good knowledge on relations and even you will never miss atleast one answer on this topic. So that It can fetch you full marks. who are preparing for IBPS, SSC, SBI, RRB or any other exams should have easy hands on age topic for getting good score.

## Important Formulas on "Problems on Ages" :

### Questions and Answers on Ages:

1. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

A.35

B.40

C.45

D.30

Answer : Option A

Explanation :

Let the present P and Q age is : 3x and 4x respectively.

whenever comes these type of questions like ten years "ago"(-) Page is 3x-10 and Q age is 4x-10.

Ten years ago, P was half of Q in age

=>(3x–10)=½(4x–10)

=>6x–20=4x–10

=>2x=10

=>x=5

Total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

2. Father is aged three times more than his son Ranjit. After 8 years, he would be two and a half times of Ranjit's age. After further 8 years, how many times would he be of Ranjit's age?

A.3 times

B.21/2times

C.23/4times

D.2 times

Answer: Option D

Explanation:

Let Ranjit's present age be x years.

if Ranjit's age = x then Father's age = 3x

But Here given statement 3 times more than his son. so 4x.

Then, father's present age =(x + 3x) years = 4x years.

(4x + 8)=5/2(x + 8)

8x + 16 = 5x + 40

3x = 24

x = 8.

after further 8 years,

Hence, required ratio

=>4x+8+8=x+8+8

=>(4x+16)/(x+16)

=>48/24=>2

3. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju

A. 15

B. 14

C. 8

D. 10

Answer: Option D

Explanation:

Let the present Raju age is x, After 15 years Raju age is x+15

If the present Raju age is x, 5 years back Raju age is x-5

Raju age after 15 years will be 5 times his age 5 years back

x+15 = 5(x-5)

=> 4x = 40 => x = 10

4. The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years

A. 7:9

B. 7:8

C. 3:8

D. 5:8

Answer: Option B

Explanation:

Let P age and Q age is 6x years and 7x years.

If Q is 4 years old than P

Then 7x - 6x = 4 <=> x = 4

after 4 years P and Q ages Ratio is

So required ratio will be (6x+4):(7x+4) => 28:32 => 7:8

5. At present the age of the father is five times that of the age of his son. Three years hence, the father’s age would be four times that of his son. Find the present ages of the father and the son.

A. 35

B. 45

C. 40

D. 55

Answer: Option B

Explanation:

Let the present age of son = x years.

Then, the present age of father = 5x years.

3 years hence.i.e after three years (x + 3) = 5x + 3

The father’s age would be four times that of his son

4(x + 3) = 5x + 3

or, 4x + 12 = 5x + 3

x = 9 years.

Therefore, son’s age = 9 years

and father’s age = 5x=5x9=45 years.